Mon May 24 2021

Memoization is an optimization technique that speeds up programs by caching the results of previous function calls. This allows subsequent calls to reuse the cached results, avoiding time-consuming recalculation. Memoization is commonly used in dynamic programming, where problems can be broken down into simpler sub-problems. One such dynamic programming problem is calculating the nth Fibonacci number.

The Fibonacci numbers are a sequence of integers where each number is the sum of the two preceding numbers, starting with the numbers 0 and 1. A function that calculates the nth Fibonacci number is often implemented recursively.

```
def fibonacci(n):
if n <= 1:
return n
return fibonacci(n - 1) + fibonacci(n - 2)
```

The function calls of `fibonacci(4)`

can be visualized with a recursion tree.

Notice that the function is called with the same input multiple times.
Particularly, `fibonacci(2)`

is calculated from scratch twice. As the input
increases, the running time grows exponentially. This is suboptimal and can be
improved significantly using memoization.

Python 3 makes it incredibly easy to memorize functions. The
functools module included in
Pythonâ€™s standard library provides two useful
decorators for
memoization:
`lru_cache`

(new in Python 3.2) and
`cache`

(new
in Python 3.9). These decorators use a
least recently used (LRU)
cache, which stores items in order of use, discarding the least recently used
items to make room for new items.

To avoid costly repeated function calls, `fibonacci`

can be wrapped by
`lru_cache`

, which saves and returns values that have already been calculated.
The size limit of `lru_cache`

can be specified with `maxsize`

, which has a
default value of 128.

```
from functools import lru_cache
@lru_cache(maxsize=64)
def fibonacci(n):
if n <= 1:
return n
return fibonacci(n - 1) + fibonacci(n - 2)
```

The newer `cache`

decorator is equivalent to `lru_cache(maxsize=None)`

.

```
from functools import cache
@cache
def fibonacci(n):
if n <= 1:
return n
return fibonacci(n - 1) + fibonacci(n - 2)
```

Since it does not need to discard least recently used items, `cache`

is both
smaller and faster than `lru_cache`

with a size limit.

With memoization implemented, the recursion tree for `fibonacci(4)`

does not
have any nodes that occur more than twice. The running time now grows linearly,
which is much faster than the previous exponential growth.

On my 2020 M1 MacBook Air, running `fibonacci(40)`

without memoization takes
18.158 seconds. With the `cache`

decorator added it takes only 0.039 seconds.